KLUEEE Question Paper

Will you please provide me the question paper of KL University Engineering Entrance Exam KLU EEE Exam for preparation?

[shikha]

Ok, here I am providing you the question paper of KL University Engineering Entrance Exam KLU EEE Exam for preparation

KLU EEE Exam question paper

Physics-

A block ‘A’ of mass 2 kg rests on another block B of mass 8 kg which rests on a horizontal floor. The coefficient of friction between A and B is 0.2. While that between B and floor is 0.5. When a horizontal force of 25 N is applied on the block B, the force of friction between A and B is

(a) zero (b) 3.9 N (c) 5 N (d) 49 N

Temperature of the mixture of one mole of He and one mole of Hydrogen is increased from 00 C to 1000C at constant pressure, the amount of heat delivered will be (R = 2 cal/mole – K)

(a) 600 cal (b) 1200 cal (c) 1800 cal (d) 3600 cal

In Huygen’s eyepiece, the distance between the two lenses is ‘P’, the effective focal length is ‘Q’, the focal length of field lens is ‘R’ and focal length of eye lens is ‘S’ then

(a) R > P > Q > S (b) P > Q > R > S (c) Q > R > S > P (d) R > S > P >

A wire of length L and 3 identical cells of negligible internal resistances are connected in series. Due to the current, the temperature of the wire is raised by T in a time ‘t’. A number ‘N’ of similar cells is now connected in series with a wire of the same material and cross – section but of length 2 L. The temperature of the wire is raised by the same amount in the same time. The value of N is

(a) 4 (b) 6 (c) 8 (d) 9

Three rods A, B and C of the same length and same cross-sectional area are joined in series. Their thermal conductivities are in the ratio 1 : 2 : 1.5. If the open ends of A and C are at 2000C and 180C respectively, the temperature at the junction of A and B in equilibrium is

(a) 1560C (b) 740C (c) 1160C (d) 1480C

An object of mass 5 kg falls from rest through a vertical distance of 20 m and attains a velocity of 10 m/s. Then the work done by the resistance of the air on the object is (g = 10 ms–2)

(a) – 750 J (b) 750 J (c) 1000 J (d) – 1000 J





For complete question paper here is the attachment