#2
| |||
| |||
Re: Placement Papers for TCS Company
Here as per your demand I am providing you TCS Company Placement Paper of Aptitude with solution 1. If f(x) = (1+x+x2+x3+.......x2012)2−x2012, g(x) = 1+x+x2+x3+.......x2011.Then what is the remainder when f(x) is divided by g(x) Let us multiply g(x) with x on the both sides x.g(x) = x+x2+x3+.......x2012 add 1 on both sides x. g(x) + 1 = 1+x+x2+x3+.......x2012 Substitute this value in f(x) then f(x) = (x.g(x)+1)2−x2012 f(x) = x2.g(x)2+2.g(x)+1−x2012 Now f(x) is divisible by g(x) first two terms are exactly divisible by g(x) and we get 1 - x2012 But 1 - x2012 = (1 - x)(1+x+x2+x3+.......x2011) if this expression is divisible by g(x) we get 0 as remainder. 2. A number has exactly 3 prime factors, 125 factors of this number are perfect squares and 27 factors of this number are perfect cubes. overall how many factors does the number have? We know that the total factors of a number N = ap.bq.cr .... Now the total factors which are perfect squares of a number N = ([p2]+1).([q2]+1).([r2]+1).... where [x] is greatest intezer less than that of x. Given ([p2]+1).([q2]+1).([r2]+1).... = 125 So [p2]+1 = 5; [q2]+1 = 5; [p2]+1 = 5 [p2] = 4 ⇒ p = 8 or 9, similarly q = 8 or 9, r = 8 or 9 Given that 27 factors of this number are perfect cubes so ([p3]+1).([q3]+1).([r3]+1).... = 27 So [p3]+1 = 3 ⇒ = [p3] = 2 ⇒ p = 6, 7, 8 By combining we know that p = q = r = 84 Number of factors of this number = (8+1).(8+1).(8+1) = 729 3. In a class there are 60% of girls of which 25% poor. What is the probability that a poor girl is selected is leader? Assume total students in the class = 100 Then Girls = 60% (100) = 60 Poor girls = 25% (60) = 15 So probability that a poor girls is selected leader = Poor girls / Total students = 15/100 = 15% 4. A and B are running around a circular track of length 120 meters with speeds 12 m/s and 6 m/s in the same direction. When will they meet for the first time? A meets B when A covers one round more than B. A's relative speed = (12 - 6) m/s. So he takes 120 / 6 seconds to gain one extra round. So after 20 seconds A meets B. 5. A completes a work in 20 days B in 60 days C in 45 days. All three persons working together on a project got a profit of Rs.26000 what is the profit of B? We know that profits must be shared as the ratio of their efficiencies. But efficiencies are inversely proportional to the days. So efficiencies of A : B : C = 1/20 : 1/60 : 1/45 = 9 : 3 : 4 So B share in the total profit = 3 / 13 X 26000 = Rs.6000 6. A completes a piece of work in 3/4 of the time in B does, B takes 4/5 of the time in C does. They got a profit of Rs. 40000 how much B gets? Assume C takes 20 Days. Now B takes 4/5 (20) = 16 days. A takes 3/4(16) = 12 Now their efficiencies ratio = 1/20 : 1/16 : 1/12 = 12 : 15 : 20 B's share in the profit of Rs.40000 = 15/47 (40000) = Rs.12765 7. An empty tank be filled with an inlet pipe ‘A’ in 42 minutes. After 12 minutes an outlet pipe ‘B’ is opened which can empty the tank in 30 minutes. After 6 minutes another inlet pipe ‘C’ opened into the same tank, which can fill the tank in 35 minutes and the tank is filled. Find the time taken to fill the tank? Assume total tank capacity = 210 Liters Now capacity of pipe A = 210/42 = 5 Liters Capacity of B = 210 / 30 = - 7 Liters Capacity of C = 210 / 35 = 6 min Assume tank gets filled in x min after the third pipe got opened. So x×5+6×(−2)+4x=210 ⇒48+4x=210⇒4x=162⇒x=40.5 Total time taken to fill the tank = 40.5 + 12 + 6 = 51.5 8. Mother, daughter and an infant combined age is 74, and mother's age is 46 more than daughter and infant. If infant age is 0.4 times of daughter age, then find daughters age. Assume M + D + I = 74; .................(1) Also given M - D - I = 46 ⇒ M = D + I + 46 Also I = 0.4 D ⇒ I = 2/5 D Substituting M and I values in the first equation we get D - 25D - 46 + D + 25D = 74 Solving D = 10 9. A Grocer bought 24 kg coffee beans at price X per kg. After a while one third of stock got spoiled so he sold the rest for $200 per kg and made a total profit of twice the cost. What must be the price of X? Total Cost price = 24×X As 1/3rd of the beans spoiled, remaining beans are 2/3 (24) = 16 kgs Selling price = 200 × 16 = 3200 Profit = Selling price - Cost price = 3200 - 24×X Given Profit = 2 × Cost price 3200 - 24×X = 2 × (24×X) Solving X = 44.44 10. Bhanu spends 30% of his income on petrol on scooter 20% of the remaining on house rent and the balance on food. If he spends Rs.300 on petrol then what is the expenditure on house rent? Given 30% (Income ) = 300 ⇒ Income = 1000 After having spent Rs.300 on petrol, he left with Rs.700. His spending on house rent = 20% (700) = Rs.140 11. Let exp(m,n) = m to the power n. If exp(10, m) = n exp(2, 2) where to and n are integers then n = Given 10m=n.22 ⇒ 2m×5m=n.22⇒2m−2×5m=n For m = 2 we get least value of n = 25, and for m > 2 we get infinite values are possible for n. 12. How many kgs. of wheat costing Rs. 5 per kg must be mixed with 45 kg of rice costing Rs. 6.40 per kg so that 20% gain may be obtained by selling the mixture at Rs. 7.20 per kg ? If the selling price of the mixture is Rs.7.2 when sold at 20% profit then CP ×120100 = 7.2 ⇒ CP = Rs.6 Now by applying weighted average formula = K×5+45×6.4K+45=6 ⇒ K = 18 kgs 13. The diagonal of a square is twice the side of equilateral triangle then the ratio of Area of the Triangle to the Area of Square is? Let the side of equilateral triangle = 1 unit. We know that area of an equilateral triangle = 3√4a2 As side = 1 unit area of the equilateral triangle = 3√4 Now Diagonal of the square = 2 (side of the equilateral triangle) = 2 We know that area of the square = 12D2 where D = diagonal So area of the square = 12(22)=2 Ratio of the areas of equilateral triangle and square = 3√4 : 2 ⇒ 3√:8 14. Raj tossed 3 dices and there results are noted down then what is the probability that raj gets 10? Always remember when 3 dice are rolled the number of ways of getting n ( where n is the sum of faces on dice) = (n−1)C2 where n = 3 to 8 = 25 where n = 9, 12 = 27 where n = 10, 11 = (20−n)C2 where n = 13 to 18 The required probability = 2763 = 27216 |
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
National Insurance Company Solved Papers | Unregistered | Main Forum | 1 | 1st February 2018 12:59 PM |
HPCL Placement Papers ECE | Unregistered | Main Forum | 1 | 22nd December 2016 02:33 PM |
CTS Placement Papers | Unregistered | Online MBA Discussions | 1 | 21st November 2015 10:56 AM |
IBM Placement Papers | Unregistered | Main Forum | 1 | 20th November 2015 03:47 PM |
Previous year placement papers of Syntel Company | Unregistered | Online MBA Discussions | 1 | 17th November 2015 10:49 AM |
TCS Placement papers | Unregistered | Main Forum | 1 | 16th November 2015 08:36 AM |
How may I get placement papers of TCS? | Unregistered | Main Forum | 1 | 12th November 2015 04:07 PM |
CTS Placement Papers | Unregistered | Main Forum | 1 | 12th November 2015 12:06 PM |
TCS Latest placement papers | Unregistered | Main Forum | 1 | 10th November 2015 05:23 PM |
TCS Placement Papers with answer | Unregistered | Main Forum | 2 | 10th November 2015 02:36 PM |
CTS Placement Papers | Unregistered | Main Forum | 1 | 10th November 2015 02:33 PM |
Oracle Placement Papers | Unregistered | Main Forum | 1 | 10th November 2015 01:22 PM |
Persistent Company Placement Paper | Unregistered | Main Forum | 1 | 9th November 2015 05:39 PM |
Placement question papers of past years of ABB Company | Unregistered | Main Forum | 1 | 9th November 2015 05:16 PM |
Wipro Placement Papers | Unregistered | Main Forum | 1 | 9th November 2015 01:54 PM |
Capgemini Placement Papers | Unregistered | Main Forum | 1 | 9th November 2015 01:28 PM |
Placement Papers Of Thomson Reuters Company | Unregistered | Main Forum | 1 | 9th November 2015 11:56 AM |
Solved Question Papers from Company Law | dg.ramya | Main Forum | 1 | 17th January 2013 03:12 PM |
EIL Placement Papers Computer | maria605 65 | Main Forum | 1 | 8th October 2012 02:08 PM |
BHEL Placement Papers | ravsaheb. | Main Forum | 1 | 6th September 2012 10:50 AM |
|